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Consider an address directly connected if the gateway of its matching routing

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table is exactly the same as the address. This is how it appears to work on Mac
OS X. Now there are three ways for an address to be directly connected:

1. Gateway address is 0.0.0.0 (Linux).
2. Gateway address is the same as local interface address (Windows).
3. Gateway address is the same as the destination address (Mac OS X).
This commit is contained in:
david
2010-03-12 00:45:11 +00:00
parent 19bd7de82c
commit d109ff13d8
1 changed files with 4 additions and 2 deletions
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6
tcpip.cc
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@@ -3668,9 +3668,11 @@ bool route_dst(const struct sockaddr_storage * const dst,
rnfo->ii = *routes[i].device;
/* At this point we don't whether this route is direct or indirect ("G" flag
in netstat). We guess that a route is direct when the gateway address is
0.0.0.0 or it exactly matches the interface address. */
0.0.0.0, when it exactly matches the interface address, or when it
exactly matches the destination address. */
rnfo->direct_connect = (routes[i].gw.s_addr == 0) ||
(routes[i].gw.s_addr == ((struct sockaddr_in *) &routes[i].device->addr)->sin_addr.s_addr);
(routes[i].gw.s_addr == ((struct sockaddr_in *) &routes[i].device->addr)->sin_addr.s_addr) ||
(routes[i].gw.s_addr == dstsin->sin_addr.s_addr);
if (!o.spoofsource)
rnfo->srcaddr = routes[i].device->addr;
ifsin = (struct sockaddr_in *) &rnfo->nexthop;