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40b0f784e7
server with a date in 2007 was producing the output |_ http-date: Sun, 07 Jan 2007 08:17:36 GMT; -918d13h46m40s from local time. Now it is |_ http-date: Sun, 07 Jan 2007 09:01:44 GMT; -2y187d13h46m40s from local time.
113 lines
3.1 KiB
Lua
113 lines
3.1 KiB
Lua
description = [[
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Gets the date from HTTP-like services. Also prints how much the date
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differs from local time. Local time is the time the HTTP request was
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sent, so the difference includes at least the duration of one RTT.
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]]
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---
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-- @output
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-- 80/tcp open http
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-- |_ http-date: Mon, 13 Jul 2009 22:44:27 GMT; -5s from local time.
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-- 80/tcp open http
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-- |_ http-date: Sun, 07 Jan 2007 08:57:52 GMT; -2y187d13h46m40s from local time.
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author = "David Fifield <david@bamsoftware.com>"
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license = "Same as Nmap--See http://nmap.org/book/man-legal.html"
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categories = {"discovery", "safe"}
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require("http")
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require("shortport")
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portrule = shortport.port_or_service({80, 443, 631, 8080},
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{"http", "https", "ipp", "http-alt"})
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-- Turn a positive or negative number of seconds into a string in one of the
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-- forms. Signs can of course vary.
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-- 0s
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-- -4s
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-- +02m38s
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-- -9h12m34s
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-- +5d17h05m06s
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-- -2y177d10h13m20s
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local function format_difftime(t2, t1)
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local d, s, sign, yeardiff
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d = os.difftime(os.time(t2), os.time(t1))
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if d > 0 then
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sign = "+"
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elseif d < 0 then
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sign = "-"
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t2, t1 = t1, t2
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d = -d
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else
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sign = ""
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end
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-- t2 is always later than or equal to t1 here.
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-- The year is a tricky case because it's not a fixed number of days
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-- the way a day is a fixed number of hours or an hour is a fixed
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-- number of minutes. For example, the difference between 2008-02-10
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-- and 2009-02-10 is 366 days because 2008 was a leap year, but it
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-- should be printed as 1y0d0h0m0s, not 1y1d0h0m0s. We advance t1 to be
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-- the latest year such that it is still before t2, which means that its
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-- year will be equal to or one less than t2's. The number of years
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-- skipped is stored in yeardiff.
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if t2.year > t1.year then
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local tmpyear = t1.year
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-- Put t1 in the same year as t2.
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t1.year = t2.year
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d = os.difftime(os.time(t2), os.time(t1))
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if d < 0 then
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-- Too far. Back off one year.
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t1.year = t2.year - 1
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d = os.difftime(os.time(t2), os.time(t1))
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end
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yeardiff = t1.year - tmpyear
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t1.year = tmpyear
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else
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yeardiff = 0
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end
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-- Seconds.
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local sec = d % 60
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s = string.format("%gs", sec)
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d = math.floor(d / 60)
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if d == 0 and yeardiff == 0 then return sign .. s end
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-- Minutes.
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s = string.format("%02dm%02ds", d % 60, sec)
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d = math.floor(d / 60)
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if d == 0 and yeardiff == 0 then return sign .. s end
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-- Hours.
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s = string.format("%dh", d % 24) .. s
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d = math.floor(d / 24)
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if d == 0 and yeardiff == 0 then return sign .. s end
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-- Days.
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s = string.format("%dd", d) .. s
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if yeardiff == 0 then return sign .. s end
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-- Years.
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s = string.format("%dy", yeardiff) .. s
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return sign .. s
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end
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action = function(host, port)
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-- Get the local date in UTC.
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local request_date = os.date("!*t")
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local response = http.get(host, port, "/")
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if not response.status or not response.header["date"] then
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return
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end
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local response_date = http.parse_date(response.header["date"])
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if not response_date then
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return
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end
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-- Should account for estimated RTT too.
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local diff = format_difftime(response_date, request_date)
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return string.format("%s; %s from local time.",
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response.header["date"], diff)
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end
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